This tool calculates the total power for a set of any number of resistors in parallel.

Enter the

**Voltage**and**Resistor values**, each separated by a comma

**Formula**

**R _{total} = (1/R_{1} + 1/R_{2} + 1/R_{3 }+…. + 1/R_{n})^{-1}**

**P = V ^{2}/R_{total}**

**Example Calculations**

For a configuration with three resistors in parallel: 1 Ω, 6 Ω, 15 Ω, 20 Ω and 1 Volt source, the total power dissipation is 1.28 Watt.

If there’s only one resistor having 1 Ω value, the power dissipated is 1 Watt.