This tool calculates the equivalent inductance of any number of inductors in parallel.
Enter the inductor values separated by commas.
Parallel Resistance Formula
Ltotal = (1/L1 + 1/L2 + 1/L3 +…. + 1/Ln)-1
Units for Inductance are Henry abbreviated as ‘H’.
Consider four inductors in parallel: 1 H, 6 H, 15 H and 100 H. The total effective inductance is 0.80 H.
If you have two resistors – one large and the other small in parallel, the effective resistance is closer to the smaller value. Take for instance 1 H and 100 H in parallel. The effective resistance is 0.99 ≈ 1 H.