This tool calculates the equivalent inductance of **any number of inductors in parallel.**

Enter the inductor values separated by commas.

**Parallel Resistance Formula**

**L _{total} = (1/L_{1} + 1/L_{2} + 1/L_{3 }+…. + 1/L_{n})^{-1}**

Units for Inductance are Henry abbreviated as ‘H’.

**Example Calculation**

Consider four inductors in parallel: 1 H, 6 H, 15 H and 100 H. The total effective inductance is 0.80 H.

If you have two resistors – one large and the other small in parallel, the effective resistance is closer to the smaller value. Take for instance 1 H and 100 H in parallel. The effective resistance is 0.99 ≈ 1 H.